Allied & ICAR Exam Bank • ALLIED_0063 NAT • 2 Marks

Section 1: Engineering Mathematics

Vector Calculus

Subtopic: Vector differential operators – del, gradient

Question Statement:

The maximum rate of increase of $\phi = 2x^2 + 3y^2$ at the point $(1, 1)$ is (rounded off to two decimal places):

Answer Key:

7.21

Step-by-Step Solution & Explanation

Maximum rate of increase is $|\nabla \phi|$. $\nabla \phi = 4x\hat{i} + 6y\hat{j} = 4\hat{i} + 6\hat{j}$. $|\nabla \phi| = \sqrt{4^2 + 6^2} = \sqrt{16 + 36} = \sqrt{52} \approx 7.211$.
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