Allied & ICAR Exam Bank • ALLIED_0133 NAT • 2 Marks

Section 2: Farm Machinery

Machine Design

Subtopic: Design and selection of machine elements – gears, pulleys, chains and sprockets and belts

Question Statement:

In a roller chain drive, pitch $p = 19.05\text{ mm}$ ($3/4\text{ in}$) and sprocket teeth $z = 20$. The pitch circle diameter of the sprocket in mm is (rounded off to one decimal place):

Answer Key:

121.8

Step-by-Step Solution & Explanation

Pitch diameter $D = \frac{p}{\sin(\pi / z)} = \frac{19.05}{\sin(180^\circ / 20)} = \frac{19.05}{\sin 9^\circ} = \frac{19.05}{0.1564} \approx 121.77\text{ mm}$.
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