Allied & ICAR Exam Bank • ALLIED_0254 NAT • 2 Marks

Section 3: Farm Power

Farm Power

Subtopic: Power efficiencies and measurement, engine performance curves

Question Statement:

A Prony brake dynamometer has brake arm length $1.0\text{ m}$. When the engine runs at $1500\text{ rpm}$, net load on the brake scale is $200\text{ N}$. Brake power in kW is (rounded off to two decimal places):

Answer Key:

31.42

Step-by-Step Solution & Explanation

Torque $T = F \times r = 200 \times 1.0 = 200\text{ N}\cdot\text{m}$. $BP = (2\pi N T)/60000 = (2\pi \times 1500 \times 200)/60000 = 31.416\text{ kW}$.
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