Allied & ICAR Exam Bank • ALLIED_0256 NAT • 2 Marks

Section 3: Farm Power

Farm Power

Subtopic: Power efficiencies and measurement, engine performance curves

Question Statement:

A 4-stroke diesel engine has volumetric efficiency $85\%$. Displacement volume is $3.0\text{ L}$ ($0.003\text{ m}^3$). At $1800\text{ rpm}$, ambient air density is $1.2\text{ kg/m}^3$. Mass flow rate of air inducted in kg/h is (rounded off to one decimal place):

Answer Key:

165.2

Step-by-Step Solution & Explanation

Intake cycles per minute $= 1800 / 2 = 900\text{ cycles/min}$. Air volume/min $= 0.003 \times 900 \times 0.85 = 2.295\text{ m}^3/\text{min}$. Mass/min $= 2.295 \times 1.2 = 2.754\text{ kg/min}$. Per hour $= 2.754 \times 60 = 165.24\text{ kg/h}$.
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