Allied & ICAR Exam Bank • ALLIED_0258 NAT • 2 Marks

Section 3: Farm Power

Farm Power

Subtopic: Calculation of power, torque, fuel consumption, heat load and power losses

Question Statement:

An engine operating at $2400\text{ rpm}$ has mean effective pressure $0.8\text{ MPa}$. Displacement volume is $2.0\text{ L}$ ($0.002\text{ m}^3$). If it is a 4-stroke engine, indicated power in kW is:

Answer Key:

32

Step-by-Step Solution & Explanation

$IP = (P_m \times V_d \times n)/60$ where $n = 2400 / 2 = 1200$. $IP = (800\text{ kPa} \times 0.002 \times 1200)/60 = 32.0\text{ kW}$.
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