Allied & ICAR Exam Bank • ALLIED_0260 NAT • 2 Marks

Section 3: Farm Power

Farm Power

Subtopic: Power efficiencies and measurement, engine performance curves

Question Statement:

A 4-cylinder 4-stroke engine develops $30\text{ kW}$ total brake power with all cylinders firing. When cylinders 1, 2, 3, and 4 are cut out individually, the brake power values are $21.5, 22.0, 21.0,\text{ and } 21.5\text{ kW}$ respectively. Total indicated power via Morse test in kW is:

Answer Key:

36

Step-by-Step Solution & Explanation

$IP_1 = 30 - 21.5 = 8.5\text{ kW}$. $IP_2 = 30 - 22.0 = 8.0\text{ kW}$. $IP_3 = 30 - 21.0 = 9.0\text{ kW}$. $IP_4 = 30 - 21.5 = 8.5\text{ kW}$. Total $IP = 8.5 + 8.0 + 9.0 + 8.5 = 36.0\text{ kW}$.
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