Allied & ICAR Exam Bank • ALLIED_0327 NAT • 2 Marks

Section 3: Farm Power

Farm Power

Subtopic: Traction theory

Question Statement:

A tractor drive wheel makes 20 revolutions over a measured $80\text{ m}$ distance without load. Under load over the same distance, it makes 24 revolutions. The wheel slip percentage is (rounded off to two decimal places):

Answer Key:

16.67

Step-by-Step Solution & Explanation

$S = ((24 - 20)/24) \times 100 = (4/24) \times 100 = 16.67\%$.
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