Allied & ICAR Exam Bank • ALLIED_0360 NAT • 2 Marks

Section 4: Soil and Water Conservation Engineering

Fluid Mechanics in SWCE

Subtopic: Fluid Mechanics in SWCE

Question Statement:

For a $90^\circ$ triangular V-notch ($\theta = 90^\circ$, $\tan(\theta/2) = 1.0$) with $C_d = 0.60$ and $g = 9.81\text{ m/s}^2$, the head over the notch is $H = 0.30\text{ m}$. The discharge in $\text{m}^3/\text{s}$ is (rounded off to three decimal places):

Answer Key:

0.070

Step-by-Step Solution & Explanation

$Q = \frac{8}{15}(0.60)\sqrt{19.62}(0.30)^{2.5} = 0.32 \times 4.42944 \times 0.049295 = 0.06987\text{ m}^3/\text{s} \approx 0.070\text{ m}^3/\text{s}$.
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