Allied & ICAR Exam Bank • ALLIED_0386 NAT • 2 Marks

Section 4: Soil and Water Conservation Engineering

Open Channel Flow

Subtopic: Open Channel Flow

Question Statement:

A hydraulic jump has conjugate depths $y_1 = 0.5\text{ m}$ and $y_2 = 1.5\text{ m}$. The head loss in the jump $\Delta E = \frac{(1.5 - 0.5)^3}{4(0.5)(1.5)}$ in meters is (rounded off to two decimal places):

Answer Key:

0.33

Step-by-Step Solution & Explanation

$\Delta E = \frac{1.0^3}{4 \times 0.75} = \frac{1.0}{3.0} = 0.333\text{ m} \approx 0.33\text{ m}$.
← Previous (ALLIED_0385) Next (ALLIED_0387) →

Practice In Authentic CBT Exam Interface

Test your skills under authentic timed conditions with live scoring and AIR percentile ranking.

Launch CBT Mock Test