Allied & ICAR Exam Bank • ALLIED_0502 NAT • 2 Marks

Section 5: Irrigation and Drainage Engineering

Canal Design and Silt Theories

Subtopic: Canal Design and Silt Theories

Question Statement:

For an alluvial bed material with mean grain diameter $d_{mm} = 0.25\text{ mm}$, Lacey's silt factor $f = 1.76 \sqrt{0.25} = 1.76 \times 0.5$ is:

Answer Key:

0.88

Step-by-Step Solution & Explanation

$f = 1.76 \times 0.5 = 0.88$.
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