Allied & ICAR Exam Bank • ALLIED_0510 NAT • 2 Marks

Section 5: Irrigation and Drainage Engineering

Canal Design and Silt Theories

Subtopic: Canal Design and Silt Theories

Question Statement:

In an earthen channel, the bed shear stress is $\tau_0 = \gamma_w R S$. For unit weight of water $\gamma_w = 9810\text{ N/m}^3$, , and bed slope $S = 1/5000 = 0.0002$, the average boundary shear stress $\tau_0$ in $\text{N/m}^2$ is (rounded off to two decimal places):

Answer Key:

1.96

Step-by-Step Solution & Explanation

$\tau_0 = 9810 \times 1.0 \times 0.0002 = 1.962\text{ N/m}^2 \approx 1.96\text{ N/m}^2$.
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