In drip irrigation, the emitter discharge equation is $q = k H^x$. For an ideal pressure-compensating (PC) emitter, the discharge exponent $x$ is:
Options:
(A) $x = 0$
(B) $x = 0.5$
(C) $x = 1.0$
(D) $x = 2.0$
Answer Key:
A
Step-by-Step Solution & Explanation
In pressure-compensating emitters, an elastomeric diaphragm adjusts orifice area under varying pressure so discharge remains constant independent of head ($q = k H^0 = k$, so $x = 0$).