Allied & ICAR Exam Bank • ALLIED_0564 NAT • 2 Marks

Section 5: Irrigation and Drainage Engineering

Centrifugal Pumps and Cavitation

Subtopic: Centrifugal Pumps and Cavitation

Question Statement:

A pump generates head $H_1 = 15\text{ m}$ at speed $N_1 = 1000\text{ rpm}$. If speed increases to $N_2 = 2000\text{ rpm}$ ($N_2/N_1 = 2.0$), the new head $H_2 = H_1 (N_2 / N_1)^2 = 15 \times 2^2$ in meters is:

Answer Key:

60

Step-by-Step Solution & Explanation

$H_2 = 15 \times 4 = 60.0\text{ m}$.
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