Allied & ICAR Exam Bank • ALLIED_0658 NAT • 2 Marks

Section 6: Agricultural Process Engineering

Material Handling Equipment

Subtopic: Material Handling Equipment

Question Statement:

In a pneumatic conveying line of diameter $D = 0.1\text{ m}$ (cross-sectional area $A = \frac{\pi}{4}(0.1)^2 \approx 0.007854\text{ m}^2$), conveying air velocity is $v = 20\text{ m/s}$. The air volumetric flow rate in $\text{m}^3/\text{s}$ is (rounded off to three decimal places):

Answer Key:

0.157

Step-by-Step Solution & Explanation

$Q = 0.007854 \times 20 = 0.15708\text{ m}^3/\text{s} \approx 0.157\text{ m}^3/\text{s}$.
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