Allied & ICAR Exam Bank • ALLIED_0829 NAT • 2 Marks

Section 2: Farm Machinery

Farm Machinery

Subtopic: Design and selection of machine elements – gears, pulleys, chains and sprockets and belts

Question Statement:

A shear bolt of diameter $d = 8.0\text{ mm}$ (shear area $A = \frac{\pi}{4}(0.008)^2 \approx 5.0265 \times 10^{-5}\text{ m}^2$) is placed at radius $R = 0.05\text{ m}$ from the PTO shaft centerline. If the bolt material has ultimate shear strength $\tau = 300\text{ MPa}$ ($3.0 \times 10^8\text{ N/m}^2$), ultimate shear force is $F = \tau A = 3.0 \times 10^8 \times 5.0265 \times 10^{-5} = 15,080\text{ N}$. The maximum torque before shearing $T = F \cdot R$ in $\text{N}\cdot\text{m}$ is (rounded off to nearest integer):

Answer Key:

754

Step-by-Step Solution & Explanation

$T = 15079.6 \times 0.05 = 753.98\text{ N}\cdot\text{m} \approx 754\text{ N}\cdot\text{m}$.
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