Farm Power

An engine running at $N = 1800\text{ rpm}$ turns through $360^\circ \times \frac{1800}{60} = 10,800^\circ\text{ per second}$ ($10.8^\circ\text{ per millisecond}$). If the total ignition delay period is $t = 1.5\text{ milliseconds}$, the ignition delay in degrees of crankshaft rotation is: