Farm Power

A 4-stroke tractor diesel engine has 4 cylinders, each of swept volume $V_s = 0.75\text{ liters}$ (total engine displacement $V_d = 4 \times 0.75 = 3.0\text{ liters} = 0.003\text{ m}^3$). At engine speed $N = 2000\text{ rpm}$, theoretical air induction rate for a 4-stroke engine is $V_{air} = \frac{V_d \times N}{2 \times 60} = \frac{0.003 \times 2000}{120}$ in $\text{m}^3/\text{s}$. The value is: