Allied & ICAR Exam Bank • ALLIED_0874 NAT • 2 Marks

Section 3: Farm Power

Farm Power

Subtopic: Tractors and Power Tillers

Question Statement:

A power tiller of engine power $8.0\text{ kW}$ operates a rotary cultivator. If $75\%\text{ of engine power}$ is transmitted directly to the rotary cultivator tines, the power delivered to the rotor in kW is:

Answer Key:

6.0

Step-by-Step Solution & Explanation

Power $= 8.0 \times 0.75 = 6.0\text{ kW}$.
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