Allied & ICAR Exam Bank • ALLIED_0876 MCQ • 1 Mark

Section 4: Soil and Water Conservation Engineering

Fluid Mechanics in SWCE

Subtopic: Fluid Mechanics in SWCE

Question Statement:

In pipe network analysis by the Hardy Cross method, the flow correction $\Delta Q$ for a closed loop with head loss $h_f = r Q^n$ is given by:

Options:

  • (A) $\Delta Q = -\frac{\sum r Q |Q|^{n-1}}{n \sum r |Q|^{n-1}}$
  • (B) $\Delta Q = -\frac{\sum Q}{\sum r}$
  • (C) $\Delta Q = \frac{\sum h_f}{\sum Q}$
  • (D) $\Delta Q = -\sum r Q^2$

Answer Key:

A

Step-by-Step Solution & Explanation

The Hardy Cross loop equation balances clockwise and counter-clockwise head losses: $\Delta Q = -\frac{\sum r Q |Q|^{n-1}}{n \sum r |Q|^{n-1}}$.
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