The theoretical volumetric capacity $Q_v$ of a horizontal screw conveyor having flight outer diameter $D$, shaft diameter $d$, pitch $s$, and rotational speed $N$ is expressed as:
Options:
(A) $Q_v = \frac{\pi}{4} (D^2 - d^2) s N$
(B) $Q_v = \pi D s N^2$
(C) $Q_v = \frac{\pi}{4} D^2 s / N$
(D) $Q_v = (D - d) s N$
Answer Key:
A
Step-by-Step Solution & Explanation
Each revolution advances an annular volume of cross-sectional area $\frac{\pi}{4}(D^2 - d^2)$ by one pitch length $s$, yielding volumetric throughput $Q_v = \frac{\pi}{4}(D^2 - d^2) s N$.