Allied & ICAR Exam Bank • ALLIED_1033 NAT • 2 Marks

Section 1: Engineering Mathematics

Differential Equations

Subtopic: Initial value problems

Question Statement:

If $\frac{dy}{dx} = -2xy$ with $y(0) = 1$, the value of $y(1)$ is:

Answer Key:

0.368

Step-by-Step Solution & Explanation

Separating variables: $\frac{dy}{y} = -2x dx \implies \ln(y) = -x^2 + C \implies y = A e^{-x^2}$. Since $y(0) = 1$, $A = 1$, so $y(x) = e^{-x^2}$. At $x=1$: $y(1) = e^{-1} = \frac{1}{2.71828} \approx 0.368$.
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