Allied & ICAR Exam Bank • ALLIED_1050 NAT • 2 Marks

Section 1: Engineering Mathematics

Calculus

Subtopic: Double integrals area

Question Statement:

The area enclosed between the parabolas $y = x^2$ and $y^2 = x$ is:

Answer Key:

0.33

Step-by-Step Solution & Explanation

The curves intersect at $(0, 0)$ and $(1, 1)$. Area $A = \int_0^1 (\sqrt{x} - x^2) dx = \left[\frac{2}{3}x^{3/2} - \frac{x^3}{3}\right]_0^1 = \frac{2}{3} - \frac{1}{3} = \frac{1}{3} \approx 0.333$.
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