Allied & ICAR Exam Bank • ALLIED_1074 NAT • 2 Marks

Section 2: Farm Machinery

Farm Machinery

Subtopic: Seeding Equipment

Question Statement:

A grain drill has a furrow opener spacing of 18 cm. To achieve a plant population of 250 plants/m$^2$ with an anticipated seedling emergence of 80%, the number of seeds that must be dropped per linear meter of row is:

Answer Key:

56.2

Step-by-Step Solution & Explanation

Row width $w = 0.18\text{ m}$. Area per meter of row length $= 1.0\text{ m} \times 0.18\text{ m} = 0.18\text{ m}^2$. Required emerged plants per linear meter $= 250 \times 0.18 = 45\text{ plants/m}$. With 80% emergence: seeds per meter $= \frac{45}{0.80} = 56.25\text{ seeds/m}$.
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