Allied & ICAR Exam Bank • ALLIED_1088 NAT • 2 Marks

Section 2: Farm Machinery

Farm Machinery

Subtopic: Grain Drill Drive Wheels

Question Statement:

A ground drive wheel of a seed drill has an effective rolling radius of 35 cm. When operated over 50 m in a tilled field, it makes 25 complete revolutions. The percentage wheel slip is:

Answer Key:

9.0

Step-by-Step Solution & Explanation

Distance without slip $= 25 \times 2\pi r = 25 \times 2 \times \pi \times 0.35\text{ m} = 54.98\text{ m}$. Actual ground travel $= 50.0\text{ m}$. Wheel slip $= \frac{54.98 - 50.0}{54.98} \times 100 = \frac{4.98}{54.98} \times 100 \approx 9.06\%$.
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