Allied & ICAR Exam Bank • ALLIED_1093 NAT • 2 Marks

Section 2: Farm Machinery

Machine Design

Subtopic: Chain Drives

Question Statement:

A roller chain drive has a driving sprocket with $z_1 = 18$ teeth rotating at $n_1 = 1200\text{ rpm}$. To drive a feed shaft at $n_2 = 400\text{ rpm}$, the number of teeth on the driven sprocket must be:

Answer Key:

54

Step-by-Step Solution & Explanation

Transmission ratio $i = \frac{n_1}{n_2} = \frac{z_2}{z_1} \implies \frac{1200}{400} = \frac{z_2}{18} \implies z_2 = 3 \times 18 = 54$.
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