Allied & ICAR Exam Bank • ALLIED_1160 NAT • 2 Marks

Section 4: Soil and Water Conservation Engineering

Open Channel Flow

Subtopic: Manning's Equation

Question Statement:

A wide rectangular grassed waterway carries flow at a depth of $y = 0.5\text{ m}$ on a bed slope $S = 0.0016$ (so $\sqrt{S} = 0.04$). For a wide channel, the hydraulic radius $R \approx y = 0.5\text{ m}$. If Manning's roughness coefficient is $n = 0.04$, the mean flow velocity in m/s is: (Take $(0.5)^{2/3} = 0.630$)

Answer Key:

0.63

Step-by-Step Solution & Explanation

$V = \frac{1}{n} R^{2/3} S^{1/2} = \frac{1}{0.04} \times (0.5)^{2/3} \times \sqrt{0.0016} = 25 \times 0.630 \times 0.04 = 0.630\text{ m/s}$.
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