Allied & ICAR Exam Bank • ALLIED_1254 NAT • 2 Marks

Section 6: Agricultural Process Engineering

Size Reduction and Milling

Subtopic: Bond's Work Index

Question Statement:

Bond's law states that energy required for size reduction is $P = 10 W_i \left(\frac{1}{\sqrt{d_2}} - \frac{1}{\sqrt{d_1}}\right)$, where $d$ is in microns and $W_i$ is Bond's work index in kW$\cdot$h/tonne. If $W_i = 12\text{ kW}\cdot\text{h/tonne}$, $d_1 = 2500\;\mu\text{m}$ ($\sqrt{d_1} = 50$), and $d_2 = 100\;\mu\text{m}$ ($\sqrt{d_2} = 10$), the power required to grind 10 tonnes/h of feed in kW is:

Answer Key:

96

Step-by-Step Solution & Explanation

$E = 10 \times 12 \left(\frac{1}{10} - \frac{1}{50}\right) = 120 (0.10 - 0.02) = 120 (0.08) = 9.6\text{ kW}\cdot\text{h/tonne}$. For 10 tonnes/h: Power $= 9.6 \times 10 = 96.0\text{ kW}$.
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