Allied & ICAR Exam Bank • ALLIED_1258NAT • 2 Marks
Section 6: Agricultural Process Engineering
Material Handling Equipment
Subtopic: Belt Conveyors
Question Statement:
A flat belt conveyor carries grain with cross-sectional loading area $A = 0.02\text{ m}^2$ at a belt speed $v = 1.5\text{ m/s}$. The grain bulk density is $\rho_b = 750\text{ kg/m}^3$. The mass conveying capacity of the belt in tonnes per hour is:
Answer Key:
81.0
Step-by-Step Solution & Explanation
Volumetric capacity $= A \times v = 0.02 \times 1.5 = 0.03\text{ m}^3/\text{s}$. Mass flow rate $= 0.03 \times 750 = 22.5\text{ kg/s}$. In tonnes/h: Capacity $= \frac{22.5 \times 3600}{1000} = 81.0\text{ t/h}$.