Allied & ICAR Exam Bank • ALLIED_2666 NAT • 2 Marks

Section 1: Engineering Mathematics

Calculus

Subtopic: Fourier, Taylor and MacLaurin series

Question Statement:

In the Fourier series of $f(x) = x^2$ in $(-\pi, \pi)$, the constant term $a_0 / 2$ is $\frac{\pi^2}{k}$. The integer $k$ is:

Answer Key:

3

Step-by-Step Solution & Explanation

$a_0 = \frac{1}{\pi} \int_{-\pi}^\pi x^2 dx = \frac{2}{\pi} \left[\frac{x^3}{3}\right]_0^\pi = \frac{2\pi^2}{3}$. Therefore $\frac{a_0}{2} = \frac{\pi^2}{3}$, so $k = 3$.
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