Allied & ICAR Exam Bank • ALLIED_2741 NAT • 2 Marks

Section 1: Engineering Mathematics

Probability and Statistics

Subtopic: Random variables

Question Statement:

If $X$ has mean $\mu = 5$ and $E[X^2] = 29$, the variance $\text{Var}(X) = E[X^2] - (E[X])^2$ is:

Answer Key:

4

Step-by-Step Solution & Explanation

$\text{Var}(X) = 29 - 5^2 = 29 - 25 = 4$.
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