Allied & ICAR Exam Bank • ALLIED_2796 NAT • 2 Marks

Section 2: Farm Machinery

Machine Design

Subtopic: Overload safety devices used in farm machinery

Question Statement:

A shear bolt of diameter $d = 8\text{ mm}$ is placed at a radius $R = 50\text{ mm}$ from the driveline axis. If the ultimate shear strength of the pin material is $\tau_u = 300\text{ MPa}$, the shear failure force of the pin ($F = \tau_u \frac{\pi}{4} d^2$) in kilonewtons is:

Answer Key:

15.08

Step-by-Step Solution & Explanation

$A = \frac{\pi}{4} (8)^2 = 50.265\text{ mm}^2$. Force $F = 300\text{ N/mm}^2 \times 50.265\text{ mm}^2 = 15079.6\text{ N} \approx 15.08\text{ kN}$.
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