Allied & ICAR Exam Bank • ALLIED_2923 NAT • 2 Marks

Section 2: Farm Machinery

Farm Machinery

Subtopic: Calculation of performance parameters – field capacity, efficiency, performance index, application rate and losses

Question Statement:

A 4-bottom tractor plow has total width $W = 1.4\text{ m}$ operating at speed $S = 5\text{ km/h}$. If the field efficiency is $\eta = 80\%$ ($0.80$), the Effective Field Capacity ($EFC$) in ha/h is:

Answer Key:

0.56

Step-by-Step Solution & Explanation

$\text{EFC} = \frac{W \times S}{10} \times \eta = \frac{1.4 \times 5}{10} \times 0.8 = 0.70 \times 0.8 = 0.56\text{ ha/h}$.
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