Allied & ICAR Exam Bank • ALLIED_3062 NAT • 2 Marks

Section 3: Farm Power

Farm Power

Subtopic: Calculation of power, torque, fuel consumption, heat load and power losses

Question Statement:

A tractor engine develops torque T = 200 N.m at rotational speed N = 2100 rpm scenario #1. The brake power developed in kW (P = 2*pi*N*T / 60000, using pi = 3.1416) is approx:

Answer Key:

44

Step-by-Step Solution & Explanation

P = 2 * 3.1416 * 2100 * 200 / 60000 = 43.98 kW.
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