Using Siebel's equation for specific heat above freezing, $c_p = 0.837 + 3.349 M$ (where $M$ is the moisture content fraction on a wet basis), the specific heat of wheat grain at $15\%$ wet basis moisture content in $\text{kJ/(kg}\cdot\text{K)}$ is ________ (round off to 2 decimal places).
Answer Key:
1.34
Step-by-Step Solution & Explanation
From Siebel's formula for agricultural produce above freezing:
$c_p = 0.837 + 3.349 M$
Given $M = 15\% = 0.15$ wet basis:
$c_p = 0.837 + 3.349(0.15) = 0.837 + 0.50235 = 1.33935\text{ kJ/(kg}\cdot\text{K)} \approx 1.34\text{ kJ/(kg}\cdot\text{K)}$