Question Bank • QB_APE_EXP_003 NAT • 2 Marks

Section 6: Agricultural Process Engineering

Engineering Properties of Agriculture Produce

Subtopic: Thermal properties

Question Statement:

Siebel's formula for the specific heat of agricultural food produce above freezing is $C_p = 0.837 + 0.0335 w$, where $w$ is the moisture content in percentage (wet basis) and $C_p$ is in $\text{kJ/(kg}\cdot\text{K)}$. For fresh fruits containing $85\%$ moisture content (w.b.), the specific heat $C_p$ in $\text{kJ/(kg}\cdot\text{K)}$ is ________ (round off to 3 decimal places).

Answer Key:

3.685

Step-by-Step Solution & Explanation

Using Siebel's equation for food products above freezing: $C_p = 0.837 + 0.0335 w$ Given $w = 85\%$: $C_p = 0.837 + 0.0335 \times 85 = 0.837 + 2.8475 = 3.6845\text{ kJ/(kg}\cdot\text{K)} \approx 3.685\text{ kJ/(kg}\cdot\text{K)}$
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