Question Bank • QB_APE_EXP_029 NAT • 2 Marks

Section 6: Agricultural Process Engineering

Size Reduction and Material Handling

Subtopic: Particle size analysis for comminuted solids

Question Statement:

A sieve analysis was performed on a $250\text{ g}$ ground feed sample using a standard set of 7 Tyler sieves. The cumulative percentages of material retained on the sieves (from coarsest to finest) were $0, 15, 35, 60, 85, 95,$ and $100\%$. The Fineness Modulus ($FM = \frac{\sum \text{cumulative } \% \text{ retained}}{100}$) of the sample is ________ (round off to 2 decimal places).

Answer Key:

3.9

Step-by-Step Solution & Explanation

Fineness modulus formula: $FM = \frac{\sum (\text{cumulative percentage retained})}{100}$ Sum of cumulative percentages: $\sum = 0 + 15 + 35 + 60 + 85 + 95 + 100 = 390\%$ $FM = \frac{390}{100} = 3.90$
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