Question Bank • QB_APE_EXP_031 NAT • 2 Marks

Section 6: Agricultural Process Engineering

Size Reduction and Material Handling

Subtopic: Size separation by screening

Question Statement:

A vibrating screen separates a feed mixture of $100\text{ kg/h}$ containing $40\%$ desired oversize material. The overflow product rate is $35\text{ kg/h}$ with $90\%$ oversize purity, and the underflow product rate is $65\text{ kg/h}$ containing $13.08\%$ oversize. The screen effectiveness based on oversize recovery ($\frac{\text{oversize in overflow}}{\text{oversize in feed}}$) in percentage is ________ (round off to 1 decimal place).

Answer Key:

78.8

Step-by-Step Solution & Explanation

1. Oversize material in feed $F x_F = 100 \times 0.40 = 40.0\text{ kg/h}$. 2. Oversize material recovered in overflow $O x_O = 35 \times 0.90 = 31.5\text{ kg/h}$. 3. Oversize recovery efficiency $E_O$: $E_O = \frac{O x_O}{F x_F} \times 100 = \frac{31.5}{40.0} \times 100 = 78.75\% \approx 78.8\%$
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