Question Bank • QB_APE_EXP_059 NAT • 2 Marks

Section 6: Agricultural Process Engineering

Evaporation and Drying

Subtopic: Drying kinetics

Question Statement:

During thin-layer drying of corn grain falling within the falling rate period following Newton's law of drying $\frac{M - M_e}{M_0 - M_e} = e^{-k t}$, the initial moisture is $M_0 = 24\%$, equilibrium moisture is $M_e = 10\%$, and the drying constant is $k = 0.35\text{ h}^{-1}$. Calculate the drying time in $\text{hours}$ required to reduce the moisture content to $13.5\%$. (All moistures dry basis)

Answer Key:

3.96

Step-by-Step Solution & Explanation

Moisture ratio ($MR$): $MR = \frac{M - M_e}{M_0 - M_e} = \frac{13.5 - 10}{24 - 10} = \frac{3.5}{14} = 0.25$ Newton's law: $MR = e^{-k t} \implies 0.25 = e^{-0.35 t}$ Taking natural logarithm: $\ln(0.25) = -0.35 t$ $-1.3863 = -0.35 t$ $t = \frac{1.3863}{0.35} \approx 3.961\text{ hours}$
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