Question Bank • QB_APE_EXP_061 NAT • 2 Marks

Section 6: Agricultural Process Engineering

Size Reduction and Material Handling

Subtopic: Fluidization of granular solids – pneumatic, bucket, screw and belt conveying

Question Statement:

A horizontal screw conveyor of screw diameter $300\text{ mm}$ with a screw pitch equal to its diameter rotates at $60\text{ rpm}$. The trough loading efficiency is $40\%$. If the bulk density of wheat is $780\text{ kg/m}^3$, calculate the volumetric conveying capacity of the screw conveyor in $\text{m}^3\text{/h}$. (Neglect shaft diameter)

Answer Key:

20.36

Step-by-Step Solution & Explanation

Volumetric capacity of a screw conveyor: $Q = 60 \times \frac{\pi}{4} D^2 \times p \times N \times \phi$ Where: - Diameter $D = 0.30\text{ m}$ - Pitch $p = 0.30\text{ m}$ - Speed $N = 60\text{ rpm}$ - Trough filling factor $\phi = 0.40$ $Q = 60 \times \frac{\pi}{4} (0.3)^2 \times 0.30 \times 60 \times 0.40$ $Q = 60 \times 0.070686 \times 0.30 \times 60 \times 0.40 = 30.536 \times 0.40 \approx 20.36\text{ m}^3\text{/h}$
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