Question Bank • QB_DFE_035 NAT • 2 Marks

Section 7: Dairy and Food Engineering

Preservation of Food

Subtopic: Kinetics of microbial death – pasteurization and sterilization of milk and other liquid foods

Question Statement:

A batch of $100000$ ($10^5$) cans of low-acid food, each initially containing $10^2$ spores of Clostridium botulinum, undergoes a commercial $12\text{-D}$ thermal sterilization process. The probability of finding a non-sterile container in the entire batch (expected number of surviving spores in the whole batch) is ________ (answer in decimal).

Answer Key:

0.00001

Step-by-Step Solution & Explanation

1. Initial total spore population across the batch of $10^5$ cans: $N_0 = 10^5 \times 10^2 = 10^7\text{ spores}$ 2. A $12\text{-D}$ reduction reduces the population by $12$ log cycles ($10^{12}$ times): $N = N_0 \times 10^{-12} = 10^7 \times 10^{-12} = 10^{-5} = 0.00001$ This represents an expected failure rate of 1 non-sterile can in $100,000$ cans.
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