Question Bank • QB_DFE_EXP_042 NAT • 2 Marks

Section 7: Dairy and Food Engineering

Preservation of Food

Subtopic: Refrigeration and cold storage basics and applications

Question Statement:

A vapor compression refrigeration plant operates with an evaporator capacity of $35.17\text{ kW}$ ($10.0\text{ Tonnes of Refrigeration}$). If the compressor consumes $8.79\text{ kW}$ of electrical power, the Coefficient of Performance ($COP = \frac{Q_{evap}}{W_{comp}}$) of the refrigeration system is ________ (answer in integer).

Answer Key:

4

Step-by-Step Solution & Explanation

Coefficient of Performance formula: $COP = \frac{\text{Refrigeration effect } Q_{evap}}{\text{Work input } W_{comp}} = \frac{35.17\text{ kW}}{8.7925\text{ kW}} = 4.0$
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