Question Bank • QB_DFE_EXP_062 NAT • 2 Marks

Section 7: Dairy and Food Engineering

Preservation of Food

Subtopic: Refrigeration and cold storage basics and applications

Question Statement:

A Carnot refrigeration cycle operates between an evaporator temperature of $-10^\circ\text{C}$ ($263.15\text{ K}$) and a condenser temperature of $30^\circ\text{C}$ ($303.15\text{ K}$). Calculate the theoretical Coefficient of Performance (COP) of the cycle.

Answer Key:

6.58

Step-by-Step Solution & Explanation

$\text{COP}_{\text{Carnot}} = \frac{T_L}{T_H - T_L} = \frac{263.15}{303.15 - 263.15} = \frac{263.15}{40} \approx 6.579$
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