Question Bank • QB_DFE_EXP_074 NAT • 2 Marks

Section 7: Dairy and Food Engineering

Heat and Mass Transfer

Subtopic: Working principles of heat exchangers

Question Statement:

A tubular heat exchanger has overall heat transfer coefficient $U = 800\text{ W/(m}^2\cdot\text{K)}$ and surface area $A = 5.0\text{ m}^2$. If the log mean temperature difference is $\text{LMTD} = 25.0^\circ\text{C}$, calculate the rate of heat transfer in $\text{kW}$.

Answer Key:

100

Step-by-Step Solution & Explanation

$Q = U \times A \times \text{LMTD} = 800\text{ W/(m}^2\cdot\text{K)} \times 5.0\text{ m}^2 \times 25.0\text{ K} = 100000\text{ W} = 100.0\text{ kW}$
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