Question Bank • QB_EM_115 NAT • 2 Marks

Section 1: Engineering Mathematics

Probability and Statistics

Subtopic: Correlation and regression analysis

Question Statement:

The two regression lines are given by $3x + 2y = 26$ and $6x + y = 31$. Calculate the correlation coefficient $r$ between $x$ and $y$.

Answer Key:

-0.5

Step-by-Step Solution & Explanation

Let the regression line of $y$ on $x$ be $3x + 2y = 26 \implies 2y = -3x + 26 \implies y = -\frac{3}{2} x + 13$, so $b_{yx} = -1.5$. Then the regression line of $x$ on $y$ is $6x + y = 31 \implies 6x = -y + 31 \implies x = -\frac{1}{6} y + \frac{31}{6}$, so $b_{xy} = -\frac{1}{6}$. Checking product: $b_{yx} \times b_{xy} = (-1.5) \times \left(-\frac{1}{6}\right) = \frac{1.5}{6} = 0.25 \le 1$ This is a valid assignment. The correlation coefficient is: $r = -\sqrt{b_{yx} \times b_{xy}} = -\sqrt{0.25} = -0.5$
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