Question Bank • QB_EM_130
NAT • 2 Marks
Section 1: Engineering Mathematics
Probability and Statistics
Subtopic: Random variables
Question Statement:
A fair six-sided die is tossed twice. Calculate the probability that the sum of the numbers obtained is equal to $8$.
Step-by-Step Solution & Explanation
Total possible outcomes $= 6 \times 6 = 36$.
Favorable outcomes with sum $= 8$ are:
$(2, 6), (3, 5), (4, 4), (5, 3), (6, 2)$ (5 outcomes).
Probability:
$P(\text{Sum} = 8) = \frac{5}{36} \approx 0.1389$
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