Question Bank • QB_EM_130 NAT • 2 Marks

Section 1: Engineering Mathematics

Probability and Statistics

Subtopic: Random variables

Question Statement:

A fair six-sided die is tossed twice. Calculate the probability that the sum of the numbers obtained is equal to $8$.

Answer Key:

0.1389

Step-by-Step Solution & Explanation

Total possible outcomes $= 6 \times 6 = 36$. Favorable outcomes with sum $= 8$ are: $(2, 6), (3, 5), (4, 4), (5, 3), (6, 2)$ (5 outcomes). Probability: $P(\text{Sum} = 8) = \frac{5}{36} \approx 0.1389$
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