(D) $\nabla \times (\nabla \times \vec{A}) = \vec{0}$ for all vector fields
Answer Key:
A, B, C
Step-by-Step Solution & Explanation
Identities A, B, and C are standard vector calculus theorems. Identity D is false because $\nabla \times (\nabla \times \vec{A}) = \nabla(\nabla \cdot \vec{A}) - \nabla^2 \vec{A}$, which is generally non-zero.