Question Bank • QB_EM_CALC_002 MCQ • 1 Mark

Section 1: Engineering Mathematics

Calculus

Subtopic: Limit, continuity and differentiability

Question Statement:

For the function $f(x) = |x|$ defined on $\mathbb{R}$, at the point $x = 0$, the function is:

Options:

  • (A) Continuous and differentiable
  • (B) Continuous but not differentiable
  • (C) Differentiable but not continuous
  • (D) Neither continuous nor differentiable

Answer Key:

B

Step-by-Step Solution & Explanation

1. Continuity at $x = 0$: $\lim_{x \to 0^+} |x| = 0, \quad \lim_{x \to 0^-} |x| = 0, \quad f(0) = 0$ Since the left and right limits both equal $f(0)$, $f(x)$ is continuous at $x = 0$. 2. Differentiability at $x = 0$: $\text{Right-hand derivative: } \lim_{h \to 0^+} \frac{|0+h| - 0}{h} = \lim_{h \to 0^+} \frac{h}{h} = 1$ $\text{Left-hand derivative: } \lim_{h \to 0^-} \frac{|0+h| - 0}{h} = \lim_{h \to 0^-} \frac{-h}{h} = -1$ Since the right-hand derivative ($+1$) does not equal the left-hand derivative ($-1$), $f(x)$ is not differentiable at $x = 0$.
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