Subtopic: Belt conveyor volumetric and gravimetric capacity
Question Statement:
A troughed belt conveyor carries grain of bulk density $\rho = 750\text{ kg/m}^3$. The cross-sectional area of the grain stream on the belt is $A = 0.035\text{ m}^2$ and the belt runs at a linear speed of $v = 1.9\text{ m/s}$. The conveying capacity is ________ $\text{tonnes/h}$ (round off to one decimal place).
Answer Key:
179.6
Step-by-Step Solution & Explanation
The gravimetric capacity of a belt conveyor is:
$C = 3600 \times A \times v \times \rho \; (\text{kg/h}) = 3.6 \times A \times v \times \rho \; (\text{t/h})$
Given $A = 0.035\text{ m}^2$, $v = 1.9\text{ m/s}$, and $\rho = 750\text{ kg/m}^3$:
$C = 3.6 \times 0.035 \times 1.9 \times 750 = 179.6\text{ tonnes/h}$