Question Bank • QB_EXP_APE_EVP_001 NAT • 2 Marks

Section 6: Agricultural Process Engineering

Evaporation & Liquid Food Concentration

Subtopic: Product rate and vapor evaporated in single effect evaporator

Question Statement:

A single-effect evaporator concentrates tomato juice from $10\%$ solids to $50\%$ solids at a feed rate of $F = 2000\text{ kg/h}$. Neglecting entrainment losses, the rate of water vapor evaporated is ________ $\text{kg/h}$ (round off to one decimal place).

Answer Key:

1600.0

Step-by-Step Solution & Explanation

From overall solids balance: $F \cdot x_F = P \cdot x_P$ $P = \frac{F \cdot x_F}{x_P} = \frac{2000 \times 0.1}{0.5} = 400.0\text{ kg/h}$ Total water vapor evaporated: $V = F - P = 2000 - 400.0 = 1600.0\text{ kg/h}$
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