Question Bank • QB_EXP_APE_PSY_033 NAT • 2 Marks

Section 6: Agricultural Process Engineering

Psychrometry & Moist Air Thermodynamics

Subtopic: Sensible heating process on psychrometric chart

Question Statement:

In the sensible heating process, air is heated from $T_{db1} = 15^\circ\text{C}$ to $T_{db2} = 55^\circ\text{C}$. Taking $c_{pa} = 1.005\text{ kJ/(kg}\cdot\text{K)}$ and $c_{pv} = 1.88\text{ kJ/(kg}\cdot\text{K)}$ with $\omega = 0.010\text{ kg/kg}$, calculate the change in enthalpy $\Delta h$ in $\text{kJ/kg dry air}$ (round off to two decimal places).

Answer Key:

40.95

Step-by-Step Solution & Explanation

$\Delta h = (c_{pa} + \omega c_{pv}) \Delta T = (1.005 + 0.010 \times 1.88) \times (55 - 15) = (1.005 + 0.0188) \times 40 = 1.0238 \times 40 = 40.952\text{ kJ/kg}$.
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